Hashmat the brave warrior C Program

Hashmat the brave warrior

Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.

Solution:
#include <stdio.h>

int main()
{
    long long int a,b;
    while(scanf("%lld %lld",&a,&b)!=EOF){
        if(a<b)
            printf("%lld\n",b-a);
        else if(a>b)
            printf("%lld\n",a-b);
    }
    return 0;
}

Input
The input contains two integer numbers in every line. These two numbers in each line denotes the number of soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2^32. Input is terminated by End of File.

Output
 For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in seperate line.

Sample Input: Sample Output:
10 12 2
10 14 4
100 200 100


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