How to write a C Program to calculate the pi by maths expression Using a array of willing value to calculated in C Programming Language ?
Solution:
/*
Program to calculate the pi by math expression
Using a array of willing value to calculated
*/
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
//to take the pi
double CountPi(int);
//function to calculate the pi's expression
int main(void)
{
printf("Exactly value of pi to compare = %1.17f\n\n", M_PI);
int i = 0;
//variable to count all willing results in to array
int N[6] = {1 ,2 ,10, 50, 100, 500};
//array with elements of willing number to calculate
double my_pi = 0.0;
//the current pi by specific value
while(i < (sizeof(N) / sizeof(N[0])))
//until all the numbers of array calculated
{
double dif_pi = 0.0;
//for the different of exactly pi
my_pi = CountPi(N[i]);
//calculate the pi with specific value
dif_pi = my_pi - M_PI;
printf("The difference is %1.17f\n\n", dif_pi);
i++;
}
return 0;
}
/* Function to calculate the pi by math expresion */
double CountPi(int n)
//n = N
{
int i = 1;
//number to calculate until n
double sum = 0.0;
//total addition of expression
double nume_1,s_fr1,deno_1;
//nume_1->numerator , deno_1->denominator , s_fr1->fraction of math expression
while(i <= n)
//addition until the willing value
{
nume_1 = pow(i - 0.5 , 2);
deno_1 = pow( n , 2);
s_fr1 = 1.0 + (nume_1 / deno_1);
sum += 1.0 / s_fr1;
i++;
}
sum *= 4;
sum /= n;
printf("pi(%d) = %1.17f\n", n, sum);
return sum;
//returning the calculating value of pi
}
