C Program Simple linked list

C Program Simple linked list

How to write a C Program Simple Linked List in C Programming Language ?


The following program shows how a simple, linear linked list can be constructed in C, using dynamic memory allocation and pointers.

Solution 1:
#include<stdlib.h>
#include<stdio.h>

struct list_el {
   int val;
   struct list_el * next;
};

typedef struct list_el item;

void main() {
   item * curr, * head;
   int i;

   head = NULL;

   for(i=1;i<=10;i++) {
      curr = (item *)malloc(sizeof(item));
      curr->val = i;
      curr->next  = head;
      head = curr;
   }

   curr = head;

   while(curr) {
      printf("%d\n", curr->val);
      curr = curr->next ;
   }



Solution 2 :

/*simple linked list*/

#include <stdio.h>



int main(void)

{

    struct entry

    {

        int value;

        struct entry* next;

    }n1, n2, n3, *list_pointer;

      

    n1.value = 100;

    n1.next = &n2;

  

    n2.value = 200;

    n2.next = &n3;

  

    n3.value = 300;

    n3.next = (struct entry *) 0;

  

    list_pointer = &n1;

  

    while (list_pointer !=n3.next)

    {

        printf("%i\n", list_pointer->value);

        list_pointer = list_pointer->next;

    }

    return 0;

}










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